X=2(x)^2-2x+4

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Solution for X=2(x)^2-2x+4 equation: 



X=2(X)^2-2X+4

We move all terms to the left:

X-(2(X)^2-2X+4)=0

We get rid of parentheses

-2X^2+X+2X-4=0

We add all the numbers together, and all the variables

-2X^2+3X-4=0

a = -2; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·(-2)·(-4)
Δ = -23
Delta is less than zero, so there is no solution for the equation

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